Question: Beats period = Time interval between two minima T =$\frac{1}{n_{1} - n_{2}} = \frac{1}{4}\sec$ T...

Question

Beats period = Time interval between two minima

T = $\frac{1}{n_{1} - n_{2}} = \frac{1}{4}\sec$

Time interval between maximum sound and minimum sound = T/2 = 1/8 sec

Answer 1

Since there is no change in beats. Therefore the original frequency of B is

n₂ = n ₁ + x = 320 + 4 = 324

Question: Beats period = Time interval between two minima T =\(\frac{1}{n_{1} - n_{2}} = \frac{1}{4}\sec\) T...