Question

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, $KCl, CH_3OH,$ $CH_3CN.$

Answer 1

n-octane is a non-polar solvent. Therefore, the solubility of a non-polar solute is more than that of a polar solute in the n-octane.
The order of increasing polarity is:
$Cyclohexane < CH_3CN < CH_3OH < KCl$
Therefore, the order of increasing solubility is:
$KCl < CH_3OH < CH_3CN < Cyclohexane$