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Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

Base strength of (i) h3C C⊖H2h_3C \, {C} ^{\ominus} H_2 (ii) H2C=C⊖HH_2 C= {C}^{\ominus} H (iii) H−C≡C⊖H-C \equiv C^{\ominus} is in the order of

A

(ii) > (i) > (iii)

B

(iii) > (ii) > (i)

C

(i) > (iii) > (ii)

D

(i) > (ii) > (iii)

Answer

(i) > (ii) > (iii)

Explanation

Solution

Weaker the acid, strongest is its conjugate base.
Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is alkane>alkene>alkynealkane > alkene > alkyne or     CH3 C⊖H2>H2C= C⊖H>H−C≡C⊖\, \, \, \, CH_3 \, _{C}^{\ominus}H_2 > H_2C = \, _{C}^{\ominus}H > H -C \equiv _{C}^{\ominus}