Solveeit Logo

Question

Question: Base of a triangle is 9 and the height is 5. Base of another triangle is 10 and height is 6. Find th...

Base of a triangle is 9 and the height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Explanation

Solution

. Until and unless it is not pointed out in the question that the triangle we are talking about is a equilateral triangle we should always use the formulae of area for the right angled triangle i.e.
Area of triangle = 12×Base×Height\dfrac{1}{2} \times Base \times Height
2. To find the ratio of two areas we are always going to use the formulae
Ratio = A1A2\dfrac{{{A_1}}}{{{A_2}}}
Where A1A_1 stands for Area of triangle 1
And A2A_2 stands for Area of triangle 2

Complete step by step answer:
1. Let’s assume the area of first triangle = A1A_1
And, the area of the second triangle = A2A_2.
2. In the triangle we are provided with the data that the height of the triangle is 9 units and the base is 5 units.
3. Therefore, By using the area of triangle
= 12×Base×Height\dfrac{1}{2} \times Base \times Height
4. By substituting the dimensions of first triangle in the formulae we will get the area of first triangle
A1=12×9×5 A1=452 \begin{gathered} {A_1} = \dfrac{1}{2} \times 9 \times 5 \\\ {A_1} = \dfrac{{45}}{2} \\\ \end{gathered}
Therefore, the area of the first triangle is 452\dfrac{{45}}{2} unit2unit^2.
5. Now, by substituting the dimensions of second triangle in the same formulae we will get the area of second triangle
A2=12×10×6 A2=602 \begin{gathered} {A_2} = \dfrac{1}{2} \times 10 \times 6 \\\ {A_2} = \dfrac{{60}}{2} \\\ \end{gathered}
Therefore the area of the second triangle is 602\dfrac{{60}}{2} unit2unit^2.
6. Now, for finding the ratio of the area of first triangle and the second triangle we will be using the formulae
Ratio = A1A2\dfrac{{{A_1}}}{{{A_2}}}
Where A1A_1 is the area of the first triangle and A2A_2 is the area of the second triangle.
Therefore, substituting the values of A1A_1 and A2A_2 in the we will get
=452602 =4560 \begin{gathered} = \dfrac{{\dfrac{{45}}{2}}}{{\dfrac{{60}}{2}}} \\\ = \dfrac{{45}}{{60}} \\\ \end{gathered}
Diving by 15 in numerator and denominator, we will get
=34= \dfrac{3}{4}
Therefore, the ratio of areas of first triangle and second triangle is
Ratio = 3:43:4

Note: While calculating the area of triangles if you know that you might have to use the area to find other things like the ratio and lot other things that try not to simplify the answer in the same spot and let it be in the form of fraction so that later on it would be easy for you only to simplify your calculations.