Question

Balanced equation for the decomposition of Iron (III) Hydrogen Carbonate?

Answer 1

Decomposition reaction is the one in which one reactant breaks down into one or more products. When Iron (III) Hydrogen Carbonate is decomposed it produces three products. There are two decomposition reactions of Iron (III) Hydrogen Carbonate.

Complete answer:
When Iron (III) Hydrogen Carbonate is decomposed two different main products are produced along with water and carbon dioxide. The chemical formula for Iron (III) Hydrogen Carbonate is $Fe{{(HC{{O}_{3}})}_{3}}$ . We will see the two combinations of products for the decomposition of Iron (III) Hydrogen Carbonate.
In the first decomposition reaction Iron (III) Hydrogen Carbonate is decomposed into Iron (III) carbonate, water, and carbon dioxide. The balanced equation of the reaction is as follows:
$2Fe{{(HC{{O}_{3}})}_{3}}\text{ }\to \text{ }F{{e}_{2}}{{(C{{O}_{3}})}_{3}}\text{ + 3C}{{\text{O}}_{2\text{ }}}+3{{H}_{2}}O$
We can see in the balanced equation that two molecules $Fe{{(HC{{O}_{3}})}_{3}}$ produce one molecule of $F{{e}_{2}}{{(C{{O}_{3}})}_{3}}\text{ }$ , 3 molecules of $\text{C}{{\text{O}}_{2\text{ }}}$ , and 3 molecules of ${{H}_{2}}O$ .
In the second decomposition reaction of Iron (III) Hydrogen Carbonate is decomposed into Iron oxide, water, and carbon dioxide. The balanced equation of the reaction is as follows:
$2Fe{{(HC{{O}_{3}})}_{3}}\text{ }\to \text{ }F{{e}_{2}}{{O}_{3}}\text{ + 6C}{{\text{O}}_{2\text{ }}}+3{{H}_{2}}O$
We can see in the balanced equation that two molecules $Fe{{(HC{{O}_{3}})}_{3}}$ produce one molecule of $F{{e}_{2}}{{O}_{3}}$ , 6 molecules of $\text{C}{{\text{O}}_{2\text{ }}}$ and 3 molecules of ${{H}_{2}}O$ .
Both the decomposition reactions are balanced because the number of molecules of the elements is the same on both sides of the equation.
Final answer: The balanced equations for decomposition of Iron (III) Hydrogen Carbonate is:
$2Fe{{(HC{{O}_{3}})}_{3}}\text{ }\to \text{ }F{{e}_{2}}{{(C{{O}_{3}})}_{3}}\text{ + 3C}{{\text{O}}_{2\text{ }}}+3{{H}_{2}}O$
$2Fe{{(HC{{O}_{3}})}_{3}}\text{ }\to \text{ }F{{e}_{2}}{{O}_{3}}\text{ + 6C}{{\text{O}}_{2\text{ }}}+3{{H}_{2}}O$ .

Note:
In the second reaction where ferrous oxide is the product the number of molecules of carbon dioxide is doubled. This is because the major product does not have any carbon atoms. This can also be used to say that Iron (III) carbonate decomposes into $F{{e}_{2}}{{O}_{3}}$ and 3 molecules of $\text{C}{{\text{O}}_{2\text{ }}}$ .