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Question: Balance the following chemical reaction: A.\(AgN{O_3} \to Ag + N{O_2} + {O_2}\) B.\(ZnS + {O_2} ...

Balance the following chemical reaction:
A.AgNO3→Ag+NO2+O2AgN{O_3} \to Ag + N{O_2} + {O_2}
B.ZnS+O2→ZnO+SO2ZnS + {O_2} \to ZnO + S{O_2}
C.S+H2SO4→SO2+H2OS + {H_2}S{O_4} \to S{O_2} + {H_2}O
D.Zn+KOH→K2ZnO2+H2Zn + KOH \to {K_2}Zn{O_2} + {H_2}
E.NO2+H2O→HNO3+HNO2N{O_2} + {H_2}O \to HN{O_3} + HN{O_2}

Explanation

Solution

The aim is to balance the chemical reaction. First, we will understand the meaning of chemical reactions, what is the balancing of a chemical reaction, and why we need to balance the chemical reaction. We will balance every molecule.

Complete step by step answer:
The chemical reaction is defined as the representation of molecules or compounds reacting with each other to give a specific molecule or compound. The compounds or molecules which are reacting are called reactants and the compounds or molecules which are obtained by the reaction of reactants are called products. The general form of a chemical reaction in which A and B are reactants, C and D are products obtained by the reaction of reactants is given as,
A+B→C+DA + B \to C + D
Now we will understand the balancing of a chemical reaction. If the number of molecules of each element is equal in both reactants as well as products the reaction is said to be balanced. If they are not equal the reaction is unbalanced and needs to be balanced.
So we will balance the reaction one by one. Consider the reaction
(A) AgNO3→Ag+NO2+O2AgN{O_3} \to Ag + N{O_2} + {O_2}
In this reaction, every element is balanced except oxygen. In reactants the number of oxygen is 33 and in product number of oxygen is 44. So we will multiply a constant to balance the reaction. So the balanced reaction will be the reaction in which all elements are equal in reactants as well as products.
2AgNO3→2Ag+2NO2+O22AgN{O_3} \to 2Ag + 2N{O_2} + {O_2}
The balanced reaction of (B) 2ZnS+2O2→2ZnO+SO22ZnS + 2{O_2} \to 2ZnO + S{O_2}
The balanced reaction of (C) S+2H2SO4→3SO2+2H2OS + 2{H_2}S{O_4} \to 3S{O_2} + 2{H_2}O
The balanced reaction of (D) 4NO2+2H2O→2HNO3+2HNO24N{O_2} + 2{H_2}O \to 2HN{O_3} + 2HN{O_2}

Note:
Remember you can use a fraction as a multiplier in the reaction but it should make sense to the atom.
If you are using a fractional coefficient and that gives a fraction of atom will be invalid.