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Question: Balance the equation \( N{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O \) ....

Balance the equation Na2CO3+HClNaCl+CO2+H2ON{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O .

Explanation

Solution

A chemical equation in which number of atoms of all the elements are equal on both reactants and products side is known as balanced chemical reaction and if the number of atoms of all the elements on both sides (products and reactants) are not equal then the reaction is known as unbalanced chemical reaction.

Complete answer:
So, we know that, in a chemical equation, if the number of atoms of all the elements are equal on both reactants and products side it is a balanced chemical equation otherwise it is an unbalanced chemical equation.
We need to balance an unbalanced chemical equation in order to follow the “law of conservation of mass” which states that mass can neither be created nor be destroyed.
Now, if we look at given chemical equation:
Na2CO3+HClNaCl+CO2+H2ON{a_2}C{O_3} + HCl \to NaCl + C{O_2} + {H_2}O
First, we will make a table and count the number of atoms of each element on both reactant and product sides.

ElementReactant sideProduct side
Sodium, Na2211
Carbon, C1111
Oxygen, O3333
Hydrogen, H1122
Chlorine, Cl1111

Here, we can see that sodium and hydrogen atoms are not balanced.
First, we will balance the sodium atoms by multiplying NaClNaCl in the product side with 22 .
Hence, the equation becomes:-
Na2CO3+HCl2NaCl+CO2+H2ON{a_2}C{O_3} + HCl \to 2NaCl + C{O_2} + {H_2}O

ElementReactant sideProduct side
Sodium, Na2222
Carbon, C1111
Oxygen, O3333
Hydrogen, H1122
Chlorine, Cl1122

Now, hydrogen and chlorine are unbalanced. So, to balance them, we will multiply HClHCl in reactions with 2.
Na2CO3+2HCl2NaCl+CO2+H2ON{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O

ElementReactant sideProduct side
Sodium, Na2222
Carbon, C1111
Oxygen, O3333
Hydrogen, H2222
Chlorine, Cl2222

Hence, now all the atoms in reactant and product sides are equal so the balanced chemical equation is:
Na2CO3+2HCl2NaCl+CO2+H2ON{a_2}C{O_3} + 2HCl \to 2NaCl + C{O_2} + {H_2}O

Note:
While balancing any element or equation, remember it should be multiplied a number as we have done in the above case. Never try balancing an equation by changing the subscripts otherwise the molecular formula of the compound will change and it will not be the same as the compound given in the equation.