Question

B2H6 bond angles?

Answer 1

The bond angles in $B_2H_6$ are approximately 120° (terminal H-B-H), 97° (B-H-B and H(terminal)-B-H(bridging)), and 84° (bridging H-B-H).

Answer 2

Each boron atom in $B_2H_6$ is $sp^3$ hybridized, leading to a distorted tetrahedral geometry. The molecule features terminal B-H bonds and bridging B-H bonds. The main bond angles observed are:

1. Terminal H-B-H: Approximately 120°.
2. B-H-B (bridging): Approximately 97°.
3. H(terminal)-B-H(bridging): Approximately 97°.
4. Bridging H-B-H: Approximately 84°. The most significant and commonly cited angles are 120° and 97°.