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Question: For a set of 100 observations, taking assumed mean as 4, the sum of the deviations is -11 cm, and th...

For a set of 100 observations, taking assumed mean as 4, the sum of the deviations is -11 cm, and the sum of the squares of these deviations is 275 cm2cm^2. Find the coefficient of variation.

Answer

42.6%

Explanation

Solution

Let the number of observations be n=100n = 100.

The actual mean is found by correcting the assumed mean with the average deviation:

xˉ=4+11100=40.11=3.89cm\bar{x} = 4 + \frac{-11}{100} = 4 - 0.11 = 3.89 \, \text{cm}

The variance is given by:

σ2=(x4)2n=275100=2.75cm2\sigma^2 = \frac{\sum (x-4)^2}{n} = \frac{275}{100} = 2.75 \, \text{cm}^2

Thus, the standard deviation is:

σ=2.751.658cm\sigma = \sqrt{2.75} \approx 1.658 \, \text{cm}

The coefficient of variation (CV) is:

CV=(σxˉ)×100=(1.6583.89)×10042.63%\text{CV} = \left(\frac{\sigma}{\bar{x}}\right) \times 100 = \left(\frac{1.658}{3.89}\right) \times 100 \approx 42.63\%