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Question

Chemistry Question on Laws of Chemical Combinations

Average atomic weight of an element M is 51.7. If two isotopes of M,M50M, M^{50} and M52M^{52} are present, then percentage of occurrence of M50M^{50} in nature will be.

A

85%

B

15%

C

50%

D

100%

Answer

15%

Explanation

Solution

Given, Average atomic weight of element (M)=51.7(M) = 51.7
Let's assume M50M^{50} occurs with x%x\%.
Hence, M52=(100x)%M^{52} = (100 - x)\%
Average atomic weight
51.7=x×M50+(100x)×M5210051.7=\frac{x \times M^{50}+\left(100-x\right)\times M^{52}}{100}
51.7=x×50+(100x)5210051.7=\frac{x \times50+\left(100-x\right)52}{100}
5170=52002x5170 = 5200 - 2x
2x=520051702x=5200-5170
x=15x=15
Hence, %\% of M50=15%M^{50}=15\%