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Question: Audio sine waves of \(3\,KHz\) frequency is used to amplitude modulate a carrier signal of \(1.5\,MH...

Audio sine waves of 3KHz3\,KHz frequency is used to amplitude modulate a carrier signal of 1.5MHz1.5\,MHz. Which of the following statements are true?(Multiple answer correct)
(A) The sideband frequencies are 1506KHz1506\,KHz and 1494KHz1494\,KHz.
(B) The bandwidth required for amplitude modulation is 6KHz6\,KHz.
(C) The bandwidth required for amplitude modulation is 3KHz3\,KHz.
(D) The sideband frequencies are 1503KHz1503\,KHz and 1497KHz1497\,KHz.

Explanation

Solution

In order to solve the above problem, we have to know the formula of side band frequencies of audio sine waves and the carrier signal of an AM wave.

Formula Used:
The side band frequencies of an AM wave are;
(fc+fm)\left( {{f_c} + {f_m}} \right)
(fcfm)\left( {{f_c} - {f_m}} \right)
Where, fm{f_m} denotes the frequency of audio sine wave, fc{f_c} denotes the frequency of carrier signal.

Complete step by step answer:
The data given in the problem is;
Audio sine wave frequency, fm=3KHz{f_m} = 3\,KHz,
Carrier signal frequency, fc=1.5MHz{f_c} = 1.5\,MHz.
In the side band frequency formula;
(fc+fm)\left( {{f_c} + {f_m}} \right) is known as the upper side band frequency (USB),
(fcfm)\left( {{f_c} - {f_m}} \right) is known as the lower side band frequency (LSB),
By changing MHzMHz into KHzKHz,
We get fc=1500KHz{f_c} = 1500\,KHz.

Upper side band frequency (USB);
(fc+fm)\left( {{f_c} + {f_m}} \right)
substitute the values of fc{f_c} and fm{f_m} ;
(fc+fm)=1500KHz+3KHz\left( {{f_c} + {f_m}} \right) = 1500\,KHz + 3\,KHz .
(fc+fm)=1503KHz\left( {{f_c} + {f_m}} \right) = 1503\,KHz.

Lower side band frequency (LSB);
(fcfm)\left( {{f_c} - {f_m}} \right)
substitute the values of fc{f_c} and fm{f_m} ;
(fcfm)=1500KHz3KHz\left( {{f_c} - {f_m}} \right) = 1500\,KHz - 3\,KHz,
(fcfm)=1497KHz\left( {{f_c} - {f_m}} \right) = 1497\,KHz.
The upper side band frequency is 1503KHz1503\,KHz, and the lower side band frequency is 1497KHz1497\,KHz.
Also, the bandwidth of the audio sine wave is;
2fm2{f_m}
Substitute the value of audio sine wave frequency fm{f_m};
2fm=2×3KHz2{f_m} = 2 \times 3\,KHz
2fm=6KHz2{f_m} = 6\,KHz
The bandwidth of the audio sine wave 6KHz6\,KHz.

Therefore, the sideband frequencies are 1503KHz1503\,KHz and 1497KHz1497\,KHz and the bandwidth required for amplitude modulation is 6KHz6\,KHz.

Hence, the option (B) The bandwidth required for amplitude modulation is 6KHz6\,KHz and option (D) The sideband frequencies are 1503KHz1503\,KHz and 1497KHz1497\,KHz is the correct answer.

Note: The general formula for side band frequency is (fc±fm)\left( {{f_c} \pm {f_m}} \right), which is then further divided into upper side band frequency (USB) and lower sideband frequency (LSB). In case of lower side band frequency (LSB) the modulated signal is subtracted from carrier signal and In case of upper side band frequency (USB) the modulated signal is added from carrier signal.