Question: Atomic weight of boron is 10.81 and it has two isotopes $5B^{10}$and $5B^{11}$. Then ratio of \(...

Question

Atomic weight of boron is 10.81 and it has two isotopes $5B^{10}$ and $5B^{11}$ . Then ratio of $5B^{10}:_{5}B^{11}$ in nature would be.

Answer 1

Solution

Let the percentage of $B^{10}$ atoms be x, then Average atomic weight

$= \frac{10x + 11(100 - x)}{100} = 10.81 \Rightarrow x = 19\mspace{6mu}\mspace{6mu}\mspace{6mu}\mspace{6mu}\therefore\frac{N_{B^{10}}}{N_{B^{11}}} = \frac{19}{81}$ .

Question: Atomic weight of boron is 10.81 and it has two isotopes \(5B^{10}\)and \(5B^{11}\). Then ratio of \(...

Solution