Question
Question: Atomic weight of Barium is 137.34. The equivalent weight of barium in \[BaCr{O_4}\]which is used as ...
Atomic weight of Barium is 137.34. The equivalent weight of barium in BaCrO4which is used as an oxidising agent in acid medium is
A.137.34 B.45.78 C.114.45 D.68.67Solution
Hint : When we come across the dissociation of BaCrO4, we will get Ba2+ and CrO42−. Now use this to solve the problem.
Formula used:
Ew (Equivalent Weight) = nMw (Molecular weight)
Where n is n factor.
Complete step by step solution :
When we add BaCrO4 in any acid the first thing that happens is BaCrO4 dissociates into two ions which are Ba2++ and CrO42−.
BaCrO4 → Ba2++ CrO42−
In this you can clearly see that CrO42− is the one which works as an oxidising agent by changing it’s an oxidative state from +6 to +3 and gaining 3 electrons as shown below.
3e−+CrO42−→Cr3+
Here, it is clearly shown that the CrO42−accepts 3 electrons and changes its state from Cr6+ to Cr3+ and hence the n factor for this is 3.
Now, using the formula Ew (Equivalent Weight) = nMw (Molecular weight)
We will calculate the equivalent weight of Barium.
Ew = nMw
The Molecular weight of barium is 137.34 and the n factor is 3, put these values in the above equation we get,
Ew = 3137.34
Ew= 45.78
So we conclude that the equivalent weight to barium in BaCrO4is 45.78
Hence the correct option is “B”. :
Note : We must know that barium chromate (BaCrO4) is useful for burn rate modifiers in pyrotechnics. Also barium chromate is a yellow colour powder. We can use barium chromate as a corrosion inhibitor when zinc alloy electroplating surfaces. For acids, n factors as the amount of H+ ion replaced by 1 mole of acid in a reaction. For alkali, n factors as the amount of OH- ion replaced by 1 mole of alkali in a reaction.