Question
Question: Atomic orbitals involved in the hybridization of the \(S{F_6}\) molecule: A. \(3s,3{p_x},3{p_y},3{...
Atomic orbitals involved in the hybridization of the SF6 molecule:
A. 3s,3px,3py,3pz,3dz2,3dx2−y2
B. 3s,3px,3py,3pz,3dx2
C. 4s,4px,4py,4pz,3dx2−y2,dxy
D. 3s,3px,3py,3dxy,3dyz,3dxz
Solution
The atom sulfur has six valence electrons of which all are attached to fluorine atoms. One can draw the electronic configuration of a sulfur atom and decide which orbitals are involved in hybridization.
Complete step by step answer:
-First of all we will learn how to calculate the hybridization of the SF6molecule. The molecule of SF6 the central atom is sulfur which has six valence electrons in it.
-All the six valences of the sulfur atom are attached to the fluorine atom which means there are six bond pairs and zero lone pairs. Hence, the coordination number in the molecule SF6 is six.
-The coordination number six gives us the hybridization as sp3d2 which means there is one electron of s-orbital, three electrons of p-orbital, and two electrons of d-orbital that are involved in the hybridization of the SF6 molecule.
-Now let us write the electronic configuration of the SF6 molecule of which electrons are involved in the hybridization,
3s13p33d2
This shows that the two electrons from the p-orbital got promoted to d-orbital which involve in the hybridization of the molecule.
-When the electrons from the p-orbital get promoted to d-orbital the electrons get filled first in the dz2 and dx2−y2. The orbitals in the p-orbital which are involved in hybridization
-Therefore, we can say that the orbitals which are involved in the hybridization of the SF6 molecule are 3s,3px,3py,3pz,3dz2,3dx2−y2
So, the correct answer is “Option A”.
Note:
The coordination number of the SF6 molecule is six hence, the geometry of the SF6 molecule is octahedral in which the six sp2d2 hybrid orbitals are projected towards the six corners of a regular octahedron.