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Question

Mathematics Question on Differentiability

At x=32x=\frac{3}{2} the function f(x)=2x32x3f(x)=\frac{|2x-3|}{2x-3} is

A

continuous

B

discontinuous

C

differentiable

D

non-zero

Answer

discontinuous

Explanation

Solution

Given, f(x)=2x32x3f(x)=\frac{|2x-3|}{2x-3}
$ \left\{ \begin{matrix} \frac{2x-3}{2x-3}, & if & x\ge \frac{3}{2} \\ \frac{-(2x-3)}{2x-3}, & if & x