Question

At which temperature the velocity of O₂ molecule will be equal to the velocity of N₂ molecule at 0⁰C-

• A. 40⁰C
• B. 93⁰C
• C. 39⁰C
• D. Cannot be calculated

Answer 1

Answer: (C)

39⁰C

Answer 2

v_rms =$\sqrt{\frac{3RT}{M}}$ Ž T µ M [Q v_rms, R ® constant]

Ž$\frac{T_{O_{2}}}{T_{H_{2}}}$=$\frac{M_{O_{2}}}{M_{H_{2}}}$Ž$\frac{T_{O_{2}}}{(273 + 0)}$=$\frac{32}{28}$Ž$T_{O_{2}}$=312K = 39⁰C