Question

At which of the following temperature would the molecules of a gas have twice the average kinetic energy they have at 20⁰C

• A. 40⁰C
• B. 80⁰C
• C. 313⁰C
• D. 586⁰C

Answer 1

Answer: (C)

313⁰C

Answer 2

$E \propto T$ ∴ $\frac{E_{2}}{E_{1}} = \frac{T_{2}}{T_{1}}$ ⇒ $\frac{2E_{1}}{E_{1}} = \frac{T_{2}}{(20 + 273)}$

⇒ $T_{2} = 293 \times 2 = 586K = 313{^\circ}C$.