Question

At what temperature will the total KE of 0.30 mol of He be the same as the total KE of 0.40 molAr at 400 K ?

• A. 533 K
• B. 400 K
• C. 346 K
• D. 300 K

Answer 1

Answer: (A)

533 K

Answer 2

KE = $\frac{3}{2}$nRT

$\frac{3}{2}$ × 0.30 × T = $\frac{3}{2}$ × 0.4 × 400

T = 533 K