Question

At what temperature will the r.m.s. velocity of $SO_2$ be the same as that of $O_2$ at 303 K ?

• A. 403 K
• B. 303 K
• C. 606 K
• D. 273 K

Answer 1

Answer: (C)

606 K

Answer 2

$^uRMS = \sqrt{3RT/M}$
$\frac{^uO_2}{^uSO_2} = \sqrt{\frac{T_{O_2} \, M_{SO_2}}{T_{SO_2} \, M_{O_2}}}$
$^uO_2 = ^uSO_2$
$\therefore$ $T_{O_2} \, M_{SO_2} = T_{SO_2} \, M_{O_2}$
303 $\times$ 64 = $T_{SO_2} \times 32$
$T_{SO_2}$ = 606 K