Question

At what temperature, r.m.s. velocity of O₂ molecules will be 1/3 of H₂ molecules at –3⁰C ?

• A. 90 K
• B. 1167⁰C
• C. –3⁰C
• D. 207⁰C

Answer 1

Answer: (D)

207⁰C

Answer 2

(V_r.m.s.)_O2 = $\frac{1}{3}$. (V_r.m.s.)_H2

$\sqrt{\frac{3RT}{32}}$= $\frac { 1 } { 3 }$ $\sqrt{\frac{3R(270)}{2}}$ solve for T.