Question

At what temperature 28 g of $N_{2}$will occupy a volume of 20 litres at 2 atm?

• A. $300.0K$
• B. $487.2K$
• C. $289.6K$
• D. $283.8k$

Answer 1

Answer: (B)

$487.2K$

Answer 2

: $PV = nRTorT = \frac{PV}{nR}$ $\left( n = \frac{m}{M} \right)$

$T = \frac{2 \times 20 \times 28}{28 \times 0.0821} = 487.2K$