Question
Question: At what speed, the velocity head of the water is equal to the pressure head of 40 cm of mercury? \...
At what speed, the velocity head of the water is equal to the pressure head of 40 cm of mercury?
A.2.8ms−1B.10.32ms−1C.5.6ms−1D.8.4ms−1
Solution
The velocity head of water is given by the equation,
v=21ρwV2
Where ρwthe density of water,Vthe velocity of water and also vis the velocity of water head. v=21×1000×V2V=10.32ms−1P=13600×10×40×10−2P=54400ρm=13600Kgm−3
The pressure head of mercury will be given as
P=ρmgh
Where Pthe pressure head of the mercury, ρmthe density of mercury, gis the acceleration due to gravity and his denoted as the height.
These two equations are being used up here in order to solve this question.
Complete step-by-step answer:
First of all let us look at the values of density of water as well as mercury in general.
The density of water is given as,
ρw=1000Kgm−3
And also the density of mercury is written as,
ρm=13600Kgm−3
It is mentioned the velocity head of the water is equal to the pressure head of mercury.
That is, the velocity head of water is given as,
v=21ρwV2
Substituting the values will give,
v=21×1000×V2
Thus the velocity will be,
v=500V2
And the pressure head of mercury can be written in the form of an equation,
P=ρmgh
Substituting the values in it,
P=13600×10×40×10−2
Simplifying this will give,
P=54400
Now let us make a comparison in between the both equations,
Therefore we can write that,
54400=500V2
After necessary rearrangements, we can write that
V2=5544
That is,
V=10.32ms−1
Therefore the correct answer is obtained.
So, the correct answer is “Option B”.
Note: Mercury is basically an element. It is a liquid at room temperature and also it is very heavy. It will not sink in water, as it is denser. But heavy solid bodies such as iron cannonballs, will float in a pool of the silvery metal.