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Question: At what height over the earth’s pole the freefall acceleration decreases by 1 %...

At what height over the earth’s pole the freefall acceleration decreases by 1 %

A

64 km

B

16 km

C

8 km

D

32 km

Answer

32 km

Explanation

Solution

g' = g(1−2hR)2hR=1100\left( 1 - \frac { 2 h } { R } \right) \frac { 2 h } { R } = \frac { 1 } { 100 } or h = 32 km