Question
Question: At what depth below the surface of the earth acceleration due to gravity \[\prime g\prime \] will be...
At what depth below the surface of the earth acceleration due to gravity ′g′ will be half of its value at 1600 km above the surface of the earth?
A. 1.6×106m
B. 2.4×106m
C. 3.2×106m
D. 4.8×106m
Solution
The acceleration due to gravity is less for an object positioned at a height h than for one placed on the surface. The value of acceleration due to gravity (g) decreases as depth increases. At the poles, the value of g is higher, while at the equator, it is lower.
Complete step by step answer:
Let us consider that the value of g outside the earth is g1 . Therefore, variation of g outside the earth is given by;
g1=g(1−R2h)
Here, g= Acceleration due to gravity (10ms−1), h= Height above the earth surface (1600km) and R=Radius of the earth (6400).
Now, putting all the given values in the equation we will find the acceleration due to gravity outside the earth.
⇒g1=10(1−64002×1600) ⇒g1=5ms−2
Now, let us consider the variation of acceleration due to gravity g inside the earth be g11. Again, putting the same formula we will find the variation inside the earth.
g11=g(1−R2h)
Now, it is said to us that, acceleration due to gravity inside the earth will be half of acceleration outside the earth.
g11=2g1 ⇒g11=25=2.5ms−2
Now, putting all the value in the equation we will find the acceleration due to gravity inside the earth.
2.5ms−2=10(1−Rh)
After evaluating the value we will get it as
41=1−6400h
Now, from here we will find the ′h′
h=43×6400km ∴h=4.8×106m
Hence, the correct option is D.
Note: One thing to keep in mind about gravity acceleration at different heights and depths from the earth's surface is that the value of gravity acceleration at a small height from the earth's surface drops faster than the value of gravity acceleration at a depth below the earth's surface.