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Question

Chemistry Question on States of matter

At very high pressures, the compressibility factor of one mole of a gas is given by :

A

pbRT\frac{pb}{RT}

B

1+pbRT1+ \frac{pb}{RT}

C

1pbRT 1- \frac{pb}{RT}

D

1b(VRT) 1- \frac{b}{(VRT)}

Answer

pbRT\frac{pb}{RT}

Explanation

Solution

(P+aV2)(vb)=RT\left(P+\frac{a}{V^{2}}\right)\left(v-b\right)=RT
at very high pressure P>>aV2P >>\frac{a}{V^{2}}
so, aV2\frac{a}{V^{2}} is negligible
P(Vb)=RTP\left(V-b\right)=RT
PVPb=RTPV-Pb=RT
Z=1+pbRT\therefore Z=1+\frac{pb}{RT} compremibilityfactor