Solveeit Logo

Question

Question: At the top of a mountain a thermometer reads 7<sup>0</sup>C and a barometer reads 70 cm of Hg. At th...

At the top of a mountain a thermometer reads 70C and a barometer reads 70 cm of Hg. At the bottom of the mountain these read 270C and 76 cm of Hg respectively. Comparison of density of air at the top with that of bottom is

A

(a) 75/76

A

70/76

B

76/75

C

76/70

Answer

76/75

Explanation

Solution

V1=2.4×103m3V_{1} = 2.4 \times 10^{- 3}m^{3}, P1=P0=105Nm2P_{1} = P_{0} = 10^{5}\frac{N}{m^{2}} and

T1 = 300 K (given)

If area of cross-section of piston is A and it moves through distance x then increment in volume of the gas = Ax

and if force constant of a spring is k then force F = kx and pressure = FA=kxA\frac{F}{A} = \frac{kx}{A}

V2=V1+Ax=2.4×103+8×103×0.1=3.2×103V_{2} = V_{1} + Ax = 2.4 \times 10^{- 3} + 8 \times 10^{- 3} \times 0.1 = 3.2 \times 10^{- 3}andP2=P0+kxA=105+8000×0.18×103=2×105P_{2} = P_{0} + \frac{kx}{A} = 10^{5} + \frac{8000 \times 0.1}{8 \times 10^{- 3}} = 2 \times 10^{5}

From ideal gas equation P1V1T1=P2V2T2\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}105×2.4×103300=2×105×3.2×103T2\frac{10^{5} \times 2.4 \times 10^{- 3}}{300} = \frac{2 \times 10^{5} \times 3.2 \times 10^{- 3}}{T_{2}}

T2=800KT_{2} = 800K