Solveeit Logo
Login

Question

Question: At the point of intersection of the two curves shown, the concentration of B is given by ..............

At the point of intersection of the two curves shown, the concentration of B is given by ........... for, A ¾®nB :

A

nA02\frac{nA_{0}}{2}

B

A0n−1\frac{A_{0}}{n - 1}

C

nA0n+1\frac{nA_{0}}{n + 1}

D

(n−1n+1)A0\left( \frac{n - 1}{n + 1} \right)A_{0}

Answer

nA0n+1\frac{nA_{0}}{n + 1}

Explanation

Solution

[A]left = [B]formed = n × [A]decayed

A0 e–lt = n × A0 (1 – e–lt)

\ e–lt = nn+1\frac{n}{n + 1}

\ [B]formed = n × A0 × (1 – e–lt)

= n × A0 ×(1−nn+1)\left( 1 - \frac{n}{n + 1} \right)= nA0n+1\frac{nA_{0}}{n + 1}