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Question: At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a ta...

At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a target. At what distance from the target should the bomb be dropped (given g = 10 m/s2)

A

605.3 m

B

600 m

C

80 m

D

230 m

Answer

605.3 m

Explanation

Solution

The horizontal distance covered by bomb,

BC=vH×2hg=1502×8010=660mBC = v_{H} \times \sqrt{\frac{2h}{g}} = 150\sqrt{\frac{2 \times 80}{10}} = 660m

∴ The distance of target from dropping point of bomb,

AC=AB2+BC2=(80)2+(600)2=605.3mAC = \sqrt{AB^{2} + BC^{2}} = \sqrt{(80)^{2} + (600)^{2}} = 605.3m