Question

At Srinagar temperature was $-{{5}^{\circ }}C$ on Monday and then it dropped by ${{2}^{\circ }}C$ on Tuesday. What is the temperature of Srinagar on Tuesday? On Wednesday, it rose by ${{4}^{\circ }}C$. What was the temperature on this day?

Answer 1

Hint: Find the temperature by adding the temperature dropped or raised to the previous day's temperature. To get the temperature of Tuesday add it to the previous day's temperature.

Complete Step-by-Step solution:
We have been given the temperature of Srinagar on Monday = $-{{5}^{\circ }}C$.
It is said that the temperature dropped by ${{2}^{\circ }}C$ on Tuesday.
$\therefore$ Temperature on Tuesday = Temperature of Monday - ${{2}^{\circ }}C$.
$\begin{aligned} & =-{{5}^{\circ }}C-{{2}^{\circ }}C \\\ & =-{{\left( 5+2 \right)}^{\circ }}C \\\ & =-{{7}^{\circ }}C \\\ \end{aligned}$
Now we have been given that the temperature rose on by ${{4}^{\circ }}C$ on Wednesday.
Thus we need to find the temperature on Wednesday.
Temperature on Wednesday = Temperature on Tuesday + ${{4}^{\circ }}C$
$\begin{aligned} & =-{{7}^{\circ }}C+{{4}^{\circ }}C \\\ & =-{{3}^{\circ }}C \\\ \end{aligned}$
Thus, we got a temperature on Tuesday = $-{{7}^{\circ }}C$.
Temperature on Wednesday = $-{{3}^{\circ }}C$.

Note: We know that zero degree Celsius is 273.15 Kelvin. The Fahrenheit temperature range is based on settling the freezing point of water at 32 degrees and boiling point to ${{212}^{\circ }}$.
$\therefore {}^{\circ }F={}^{\circ }C*1.8+32$
Eg: - ${}^{\circ }F=-3{}^{\circ }\times 1.8+32={{26.6}^{\circ }}$ Fahrenheit.