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Physics Question on Electromagnetic induction

At room temperature, copper has free electron density of 8.4×1028m−38.4 \times {10}^{28}m^{-3}. The electron drift velocity in a copper conductor of cross-sectional area of 10−6m2 {10}^{-6}m^{2} and carrying a current of 5.4 A, will be

A

4ms−14{ms}^{-1}

B

0.4ms−10.4{ms}^{-1}

C

4cms−14{cms}^{-1}

D

0.4mms−10.4{mms}^{-1}

Answer

0.4mms−10.4{mms}^{-1}

Explanation

Solution

Drift velocity in a copper conductor
Vd=ineAV_d=\frac {i}{neA}= 5.48.4×1028×1.6×10−19×10−6\frac {5.4}{8.4 \times {10}^{28}\times 1.6 \times {10}^{-19}\times {10}^{-6}}
=0.4×10−3ms−1=0.4 \times {10}^{-3}{ms}^{-1}
0.4mms−10.4{mms}^{-1}