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Question

Mathematics Question on Differential equations

At present, a firm manufactures 1099 items. It is estimated that the rate of change of production P with respect to additional number of workers x is given by dPdx=10012x.\frac{dP}{dx}=100-12\sqrt{x}. . If the firm empower 25 more workers, then the new level of production of items is

A

20002000

B

25002500

C

30003000

D

35003500

Answer

25002500

Explanation

Solution

Given, dPdx=10012x\frac{dP}{dx}=100-12\sqrt{x} \Rightarrow dP=(10012x)dxdP=(100-12\sqrt{x})dx On integrating both sides, we get P=100x12(x3/23/2)+CP=100x-12\left( \frac{{{x}^{3/2}}}{3/2} \right)+C \Rightarrow P=100x8x3/2+CP=100x-8{{x}^{3/2}}+C ..(i) At initially x=0,P=1000x=0,\,\,\,\,P=1000 Then, from E (i) we get 1000=100×00+C1000=100\times 0-0+C \Rightarrow C=1000C=1000 On putting the value of C in E (i), we get P=100x8x3/2+1000P=100x-8{{x}^{3/2}}+1000 Now, at x=25,x=25, P=100(25)8(25)3/2+1000P=100(25)-8{{(25)}^{3/2}}+1000 =25008(125)+100=2500-8(125)+100 =35001000=2500=3500-1000=2500