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Question

Mathematics Question on Differential equations

At present, a firm is manufacturing 10001000 items. It is estimated that the rate of change of production PP with respect to additional number of workers xx is given by dPdx=10012x\frac {dP}{dx}=100-12 \sqrt x If the firm employees 2525 more workers, then the new level of production of items is

A

2500

B

3000

C

3500

D

4500

Answer

3500

Explanation

Solution

Given, dPdx=10012x\frac {dP}{dx}=100-12 \sqrt x
dP=(10012x)dx\Rightarrow \, \, \, \, dP=(100-12 \sqrt x) dx
On integrating both sides, we get
dP=(10012x)dx\, \, \, \, \, \int \limits dP= \int \limits \, (100-12 \sqrt x)dx
P=100x8x3/2+C\, \, \, \, \, \, \, \, \, \, \, \, P=100x-8x^{3/2}+ C
When x=0x=0, then P=2000C=2000P=2000 \Rightarrow C=2000
Now, when x=25x = 25, then is
P=100×258×(25)3/2+2000\, \, \, \, \, P=100 \times 25-8 \times (25)^{3/2}+2000
=25008×125+2000\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =2500-8 \times 125+2000
=45001000=3500\, \, \, \, \, \, \, \, \, \, \, \, \, \, \, =4500-1000=3500