Question

At $NTP$, $1\, L$ of $O_{2}$ reacts with $3 \,L$ of carbon monoxide. What will be the volume of $CO$ and $CO_{2}$ after the reaction?

• A. $1 \,L\, CO_{2}, 1\, L\,CO$
• B. $2 \,L\, CO_{2}, 2\, L\,CO$
• C. $1 \,L\, CO_{2}, 2\, L\,CO$
• D. $2 \,L\, CO_{2}, 1\, L\,CO$

Answer 1

Answer: (D)

$2 \,L\, CO_{2}, 1\, L\,CO$

Answer 2

\underset{\text{2,vol}}{ {2CO}}+\underset{\text{1,vol}}{ {O2}} ${->}$ \underset{\text{2,vol}}{ {2CO2}} $1$ vol of $O_{2}$ reacts with $2$ vol of $CO$ $1\, L$ of $O_{2}$ reacts with $2\, L$ of $CO$ $CO$ left after reaction $= 3 - 2 = 1\, L$ $1\, L$ of $O_2$ produces $2 \,L$ of $CO_2$. Hence, after the reaction, $CO = 1\, L, CO_2 = 2\, L$