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Question: At \(m ^ { - 3 }\), then the volume occupied by water molecules in 1 litre of steam at that temperat...

At m−3m ^ { - 3 }, then the volume occupied by water molecules in 1 litre of steam at that temperature is.

A

6

B

60

C

0.6

D

0.06

Answer

0.6

Explanation

Solution

Volume of steam = 1lt = 103 cm310 ^ { 3 } \mathrm {~cm} ^ { 3 }

∵m=d.V\because m = d . V

∴ mass of 103 cm310 ^ { 3 } \mathrm {~cm} ^ { 3 }steam = density × Volume

= 0.0006gmcm3×103 cm3\frac { 0.0006 \mathrm { gm } } { \mathrm { cm } ^ { 3 } } \times 10 ^ { 3 } \mathrm {~cm} ^ { 3 } =0.6gm= 0.6 \mathrm { gm }

Actual volume occupied by H2O\mathrm { H } _ { 2 } \mathrm { O } molecules is equal to volume of water of same mass

∴\therefore Actual volume of H2O\mathrm { H } _ { 2 } \mathrm { O } molecules in steam

= mass of steam/density of water

= ⇒0.6 cm3\Rightarrow 0.6 \mathrm {~cm} ^ { 3 }