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Question

Chemistry Question on Van Der Waals equation

At high pressure van der Waals equation becomes :

A

PV=RTPV=RT

B

PV=RT+aVPV=RT+\frac{a}{V}

C

PV=RTaVPV=RT-\frac{a}{V}

D

PV=RT+PbPV=RT+Pb

Answer

PV=RT+PbPV=RT+Pb

Explanation

Solution

van der Waals equation of state is
[P+aV2](Vb)=RT\left[ P+\frac{a}{{{V}^{2}}} \right]\,(V-b)=RT
when pressure is high, value of VV will be very small and the quantity aV2\frac{a}{V^{2}} becomes small and can be neglected in comparison to PP.
Thus, the above equation becomes P(Vb)=RTP(V-b)=RT
PVPb=RTPV-Pb=RT
PV=RT+PbPV=RT+Pb
The product PVPV becomes greater that RTRT by an amount equal to PbP-b.
This explain that curves start rising at high pressure.