Question

At constant volume the specific heat of a gas is $\frac{3R}{2},$ then the value of $\gamma$will be

• A. $\frac{3}{2}$
• B. $\frac{5}{2}$
• C. $\frac{5}{3}$
• D. None of the above

Answer 1

Answer: (C)

$\frac{5}{3}$

Answer 2

Specific heat at constant volume $C_{v} = \frac{R}{\gamma - 1} = \frac{3R}{2}$ (given)

∴ $\gamma - 1 = \frac{2}{3}$

⇒ $\gamma = \frac{5}{3}$.