Question

At constant temperature, if pressure increases by 1%, the percentage decrease of volume is

• A. 1%
• B. 100/101%
• C. 1/101%
• D. 1/100%

Answer 1

Answer: (B)

100/101%

Answer 2

$P _ { 1 } V _ { 1 } = P _ { 2 } V _ { 2 }$

If $P _ { 1 } = 100 \mathrm {~mm}$ , $P _ { 2 }$ will be 101 mm

Hence =100 × V =101 × V2

$V _ { 2 } = \frac { 100 } { 101 } \times V$ ,

Decrease in volume $= V - \frac { 100 V } { 101 } = \frac { 1 } { 101 }$ of V i.e. $\frac { 100 } { 101 } \%$