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Question: At constant pressure, density of a gas is: ![](https://www.vedantu.com/question-sets/9e6e9cc1-4fec...

At constant pressure, density of a gas is:

A. directly proportional to absolute temperature B. inversely proportional to absolute temperature C. independent of temperature D. directly proportional to square root of absolute temperature

Explanation

Solution

Before we solve this question, it is important to understand the mathematical definition of the quantity density. It is the ratio of mass of the body to its volume.
Density, ρ=mV\rho = \dfrac{m}{V}
where m = mass of the body and V = volume of the body.

Complete step-by-step solution:
For any gas, the state of the gas at any instant of time, is defined by four basic quantities : pressure P, volume V, temperature T and quantity of substance (or number of moles, n).
There are 4 laws known as Gas laws, that establish the relationship between these four state variables. They are: i) Boyle’s law: P1VP \propto \dfrac{1}{V} ii) Charles’s law: V1TV \propto \dfrac{1}{T} iii) Gay-Lussac’s law: PTP \propto T iv) Avogadro’s law: VnV \propto n
By combining these 4 individual gas laws, we obtain an important equation known as the Ideal Gas Equation.

Ideal gas equation:
PVnTPV \propto nT
By removing the proportionality, we get –
PV=nRTPV = nRT
where R = universal gas constant.
The number of moles of a gas is equal to the mass of the gas per unit molar mass (or mass of 1 mole of the gas) of the gas. Hence,
n=mMn = \dfrac{m}{M}
where m = mass of the gas, M = molar mass or mass of 1 mole of the gas
Substituting in the ideal gas equation,
PV=mMRTPV = \dfrac{m}{M}RT
By rearranging the equation,
P=mVRMTP = \dfrac{m}{V}\dfrac{R}{M}T
The density of the gas is the mass per unit volume of the gas.
Hence, ρ=mV\rho = \dfrac{m}{V}
Also, we have –
R=RMR' = \dfrac{R}{M}
where RR' is called a specific gas constant for the gas and is equal to the universal gas constant divided by the molar mass of the gas.
Thus, we have –
P=ρRTP = \rho R'T
Given, that the pressure is constant, we get –
ρ=PRT\rho = \dfrac{P}{{R'T}}
ρ1T\therefore \rho \propto \dfrac{1}{T}
Hence, the density of the gas is inversely proportional to the absolute temperature.

Hence, the correct option is Option B.

Note: The students should exercise caution while substituting the values of temperature in problems related to this equation. The temperature should be compulsorily converted to kelvin scale and cross-checked before substituting because here, it is given as absolute temperature, which is the temperature in the kelvin scale.