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Question: At a pressure of\(24 \times 10^{5}dyne/cm^{2}\), the volume of \(O_{2}\) is 10 litre and mass is 20 ...

At a pressure of24×105dyne/cm224 \times 10^{5}dyne/cm^{2}, the volume of O2O_{2} is 10 litre and mass is 20 gm. The r.m.s. velocity will be

A

800 m/sec

B

400 m/sec

C

600 m/sec

D

Data is incomplete

Answer

600 m/sec

Explanation

Solution

vrms=3PVm=3×(24×105×101)×(10×103)(20×103)v_{rms} = \sqrt{\frac{3PV}{m}} = \sqrt{\frac{3 \times (24 \times 10^{5} \times 10^{- 1}) \times (10 \times 10^{- 3})}{(20 \times 10^{- 3})}}

=600m/s.= 600m/s.