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Question

Physics Question on Magnetism and matter

At a point on the right bisector of a magnetic dipole the magnetic

A

potential varies as 1r2\frac{1}{r^2}

B

potential is zero at all points on the right bisector

C

field varies as r2r^2

D

field is perpendicular to the axis of dipole

Answer

potential varies as 1r2\frac{1}{r^2}

Explanation

Solution

The magnetic potential due to a magnetic dipole at distance rr is given by V=μ04πMcosθr2 V=\frac{\mu_0}{4\pi} \frac{M\, cos\, \theta}{r^2} On the right bisector (ie, on axial line), θ=0\theta = 0^\circ =μ04π.Mr2\therefore =\frac{\mu_0}{4\pi}.\frac{M}{r^2} or V??frac1r2V??frac{1}{r^2}