Solveeit Logo
Login

Question

Question: At a place the earth's horizontal component of magnetic field is ![](https://cdn.pureessence.tech/ca...

At a place the earth's horizontal component of magnetic field is If the angle of dip at that place is 600, then the vertical component of earth's field at that place in weber/m2 will be approximately

A

0.12×10−40.12 \times 10 ^ { - 4 }

B

0.24×10−40.24 \times 10 ^ { - 4 }

C

0.40×10−40.40 \times 10 ^ { - 4 }

D

0.62×10−40.62 \times 10 ^ { - 4 }

Answer

0.62×10−40.62 \times 10 ^ { - 4 }

Explanation

Solution

By using =BVBH⇒tan⁡60∘=BV0.38×10−4= \frac { B _ { V } } { B _ { H } } \Rightarrow \tan 60 ^ { \circ } = \frac { B _ { V } } { 0.38 \times 10 ^ { - 4 } }

⇒BV=0.38×10−4×3=0.62×10−4\Rightarrow B _ { V } = 0.38 \times 10 ^ { - 4 } \times \sqrt { 3 } = 0.62 \times 10 ^ { - 4 }