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Question

Chemistry Question on Electrochemistry

At a particular temperature, the ratio of molar conductance to specific conductance of 0.01 M NaCl solution is

A

105 cm3 mo−110^{5} \,cm^3\,mo^{-1}

B

103 cm3 mol−110^{3} \,cm^3\,mol^{-1}

C

10 cm3 mol−110 \,cm^{3}\,mol^{-1}

D

105 cm2 mol−110^{5} \, cm^2\,mol^-1

Answer

105 cm3 mo−110^{5} \,cm^3\,mo^{-1}

Explanation

Solution

∧m=kc×1000\wedge_{m} = \frac{k}{c} \times 1000
∧mk=10000.01=10310−2=105 cm3 mol−1\frac{\wedge_m}{k} =\frac{1000}{0.01} = \frac{10^3}{10^{-2}} = 10^5 \, cm^3 \,mol^{-1}