Question

At a particular locus, frequency of 'A' allele is 0.6 and that of 'a' is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium ?

• A. 0.16
• B. 0.48
• C. 0.36
• D. 0.24

Answer 1

Answer: (B)

0.48

Answer 2

frequency of heterozygotes (Aa) using the formula:
Frequency of heterozygotes (Aa) = 2 $\times$ Frequency of 'A' allele (p) $\times$ Frequency of 'a' allele (q)
Given:
Frequency of 'A' allele (p) = 0.6
Frequency of 'a' allele (q) = 0.4
Frequency of heterozygotes (Aa) = 2 $\times$ 0.6 $\times$ 0.4 = 0.48
So, the frequency of heterozygotes in a random mating population at equilibrium is 0.48.

Therefore, the correct answer is (B): 0.48