Solveeit Logo

Question

Chemistry Question on Equilibrium

At a certain temperature in a 5 L vessel, 2 moles of carbon monoxide and 3 moles of chlorine were allowed to reach equilibrium according to the reaction,CO+Cl2<=>COCl2CO + Cl_{2} <=> COCl_2 At equilibrium, if one mole of CO is present then equilibrium constant (Kc)(K_c) for the reaction is :

A

2

B

2.5

C

3

D

4

Answer

2.5

Explanation

Solution

We have

Equilibrium constant can be calculated as Kc=[COCl2][CO][Cl2]K_{ c }=\frac{\left[ COCl _{2}\right]}{[ CO ]\left[ Cl _{2}\right]}
Kc=(1mol/5L)(1mol/5L)×(2mol/5L)=2.5K_{ c }=\frac{(1 mol / 5 L )}{(1 mol / 5 L ) \times(2 mol / 5 L )}=2.5