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Question: At a certain place, the horizontal component of earth's magnetic field is \(\sqrt { 3 }\) times the...

At a certain place, the horizontal component of earth's magnetic field is 3\sqrt { 3 } times the vertical component. The angle of dip at that place is

A

60∘60 ^ { \circ }

B

45∘45 ^ { \circ }

C

90∘90 ^ { \circ }

D

30∘30 ^ { \circ }

Answer

30∘30 ^ { \circ }

Explanation

Solution

tan⁡θ=BVBH=13⇒θ=30∘\tan \theta = \frac { B _ { V } } { B _ { H } } = \frac { 1 } { \sqrt { 3 } } \Rightarrow \theta = 30 ^ { \circ }