Question

At a certain place, horizontal component is $\sqrt{3}$ times the vertical component. The angle of dip at this place is

• A. 0
• B. p/3
• C. p/6
• D. None of these

Answer 1

Answer: (C)

p/6

Answer 2

tan $=\frac{V}{H}=\frac{V}{\sqrt{3}V}=\frac{1}{\sqrt{3}}$
$\quad =30^{\circ}=\quad$ / 6 radian