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Question

Chemistry Question on Chemical Kinetics

At 518C518^{\circ} C , the rate of decomposition of sample of gaseous acetaldehyde, initially at a pressure of 363363 Torr, was 1.001. 00 Torr s1s^{-1} when 5%5\% had reacted and 0.50.5 Torr s1s^{-1} when 33%33\% had reacted. The order of the reaction is -

A

2

B

3

C

1

D

0

Answer

2

Explanation

Solution

Assume the order of reaction with respect to acetaldehyde is xx.

Rate =k[CH3CHO]x= k\, \left[ CH _{3} CHO \right]^{ x }
1=k[363×0.95]x1= k \,[363 \times 0.95]^{ x }
1=k[344.85]x...(i)1= k\, [344.85]^{ x }\,\,\,\,\,\,\,\,\,...(i)
0.5=k[363×0.67]x0.5= k\, [363 \times 0.67]^{ x }
0.5=k[243.21]x...(ii)0.5= k \,[243.21]^{ x }\,\,\,\,\,\,\,...(ii)

Divide equation (i) by (ii),

10.5=(344.85243.21)x\frac{1}{0.5}=\left(\frac{344.85}{243.21}\right)^{ x }
2=(1.414)x\Rightarrow 2=(1.414)^{ x }
x=2\Rightarrow x =2