Question
Question: At 500 K for an isobaric process. DS<sub>system</sub> = – 10 \(\frac{kJ}{molK}\) and DS<sub>surr</s...
At 500 K for an isobaric process.
DSsystem = – 10 molKkJ and DSsurr = 12 molKkJ
Therefore, DG for the entire process is-
A
–500 kJ/mol
B
–1000 kJ/mol
C
–600 kJ/mol
D
–1100 kJ/mol
Answer
–1000 kJ/mol
Explanation
Solution
DStotal = DSsystem – TΔH = 2 kJ/mol.
or TΔH–TΔS = – 2 kJ/mol.
or DH – TDS = – 2T kJ/mol. = – 2 × 500 kJ/mol = – 1000
molkJ