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Question: At \(373K\) , a gaseous reaction \(A \to 2B + C\) is found to be first-order. Starting with pure \(A...

At 373K373K , a gaseous reaction A2B+CA \to 2B + C is found to be first-order. Starting with pure AA , the total pressure at the end of 10min10\min was 176mmHg176mmHg and after a long time when AA was completely dissociated, it was 270mmHg270mmHg . The pressure of AA at the end of 10min10\min was
A.94mmHg94mmHg
B.47mmHg47mmHg
C.43mmHg43mmHg
D.90mmHg90mmHg

Explanation

Solution

Differential rate laws are used to describe the events occurring on a molecular level during a reaction whereas integrated rate laws are used for determining order of reaction and the value of rate constant during experimental conditions.

Complete step by step answer:
The given reaction is a first-order reaction. A reaction whose rate is dependent on the concentration of only one reactant is called a first-order reaction. Now in the given reaction,
A2B+CA \to 2B + C

At time =0 = 0xx0000
At t =10min= 10\minxyx - y2y2yyy

Let xx be the pressure of AA . Then the pressure of BB and CCwill be zero since at zero time there will be no product formation.
Then after 10min10\min , if pressure of product CC is considered as yy , then pressure of BB wil be 2y2y and that of AA will be xyx - y . It is given that the pressure after 10min10\min is 176mmHg176mmHg .
So, total pressure =(xy)+2y+y=176mmHg = (x - y) + 2y + y = 176mmHg
x+2y=176mmHgx + 2y = 176mmHg ……(i)
Now it is given that after 100min100\min the pressure whenAA is completely dissociated is 270mmHg270mmHg .
So, A2B+CA \to 2B + C

At t =100min= 100\min002x2xxx

Since AA is completely dissociated the pressure of CC will be equal to the initial pressure of AA which will be xx . and that of BB will be 2x2x .
So, 0+2x+x=270mmHg0 + 2x + x = 270mmHg
3x=270mmHg3x = 270mmHg
x=90mmHgx = 90mmHg
Substituting this value in equation (i),
x+2y=176mmHgx + 2y = 176mmHg
90+2y=17690 + 2y = 176
2y=176902y = 176 - 90
2y=862y = 86
y=43mmHgy = 43mmHg
Now we know that at the end of 10min10\min the pressure of AA is xyx - y .
Substituting values of xx and yy we get,
Pressure of AA =xy=9043=47mmHg = x - y = 90 - 43 = 47mmHg
So the correct option is B.

Note: The rate law equation for first order reaction is k=2.303tlogaaxk = \dfrac{{2.303}}{t}\log \dfrac{a}{{a - x}} Where kk is reaction rate coefficient, tt is the time, aa is the initial concentration of reactant and axa - x is concentration of reactant left behind after time tt .
-The unit of kk is time1tim{e^{ - 1}} .
-The unit of kk varies for every order of reaction.