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Chemistry Question on Solutions

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bars at the same temperature, what would be its concentration?

Answer

The correct answer is: 0.061 M
Here,
T= 300 K
T = 1.52 bar
R=0.083 bar LK−1mol−1R = 0.083\, bar\, LK^{-1} mol^{-1}
Applying the relation,
π=CRTπ = CRT
⇒C=πRT⇒C= \frac{π}{RT}
=1.52bar(0.083 bar LK−1mol−1×300K)= \frac{1.52 bar}{(0.083\, bar\,LK^{-1}mol^{-1}\times 300 K)}
= 0.061 mol
Since the volume of the solution is 1 L, the concentration of the solution would be 0.061 M.